tag:blogger.com,1999:blog-37105412.post2566360269034139568..comments2012-06-06T20:24:39.001-07:00Comments on The World Is A Neat Place, Usually: If I Only Could Organize A Kickstarter #1Jonathan Souzahttps://plus.google.com/115370985513488920009noreply@blogger.comBlogger2125tag:blogger.com,1999:blog-37105412.post-47255391090240440462012-06-06T20:24:39.001-07:002012-06-06T20:24:39.001-07:00True...but, my issue is that I have a short attent...True...but, my issue is that I have a short attention span-I have to solve the problem NOW.<br /><br />But, I'll start having to ask math-enabled friends at this rate. Still...I LIKE the idea and might refine it a bit more.zakueinshttp://www.blogger.com/profile/16062674796685851014noreply@blogger.comtag:blogger.com,1999:blog-37105412.post-15076421879371704402012-06-06T08:21:29.774-07:002012-06-06T08:21:29.774-07:00So, for question #1:
http://www.cthreepo.com/lab/m...So, for question #1:<br />http://www.cthreepo.com/lab/math1.shtml<br />plugging in your #s gets 2,046,971 and change miles away, doing about 158 miles/second.<br /><br />For question #3:<br />First, plot your course:<br />step 1: lift from SFO and fly to the further of:(a) 100 diameters out from Earth or (b) 100 diameters from the sun. Earth's diameter is 12,756.32; 100 diameters is thus 1,275,632 miles, and that would be the distance required. The sun's diameter is 1.4 million km; 100 diameters is thus 140 million km. Earth is (on average) 150 million km from the sun, so just outside the 100 diameter line. So, given your 1G constant acceleration drive, we need to travel to 100 earth diameters (since we're already at 100 solar diameters). How long does it take to get there? Answer? 8.6 minutes. So, after ~10 minutes from launch, you're ready to go into hyperdrive. Tau Ceti is ~12 light years away. Thus, your total mission time to arrival is basically 12 days.<br /><br />Seriously. All this stuff? Break it down into chunks, and solve the math. Ask your friends who are math-enabled. Remember John and the grav gun with the frigate-sized projectile? Right.Charleshttp://www.blogger.com/profile/12062597143743727026noreply@blogger.com